x^2+16x+14=0

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Solution for x^2+16x+14=0 equation:


Simplifying
x2 + 16x + 14 = 0

Reorder the terms:
14 + 16x + x2 = 0

Solving
14 + 16x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-14' to each side of the equation.
14 + 16x + -14 + x2 = 0 + -14

Reorder the terms:
14 + -14 + 16x + x2 = 0 + -14

Combine like terms: 14 + -14 = 0
0 + 16x + x2 = 0 + -14
16x + x2 = 0 + -14

Combine like terms: 0 + -14 = -14
16x + x2 = -14

The x term is 16x.  Take half its coefficient (8).
Square it (64) and add it to both sides.

Add '64' to each side of the equation.
16x + 64 + x2 = -14 + 64

Reorder the terms:
64 + 16x + x2 = -14 + 64

Combine like terms: -14 + 64 = 50
64 + 16x + x2 = 50

Factor a perfect square on the left side:
(x + 8)(x + 8) = 50

Calculate the square root of the right side: 7.071067812

Break this problem into two subproblems by setting 
(x + 8) equal to 7.071067812 and -7.071067812.

Subproblem 1

x + 8 = 7.071067812 Simplifying x + 8 = 7.071067812 Reorder the terms: 8 + x = 7.071067812 Solving 8 + x = 7.071067812 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = 7.071067812 + -8 Combine like terms: 8 + -8 = 0 0 + x = 7.071067812 + -8 x = 7.071067812 + -8 Combine like terms: 7.071067812 + -8 = -0.928932188 x = -0.928932188 Simplifying x = -0.928932188

Subproblem 2

x + 8 = -7.071067812 Simplifying x + 8 = -7.071067812 Reorder the terms: 8 + x = -7.071067812 Solving 8 + x = -7.071067812 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = -7.071067812 + -8 Combine like terms: 8 + -8 = 0 0 + x = -7.071067812 + -8 x = -7.071067812 + -8 Combine like terms: -7.071067812 + -8 = -15.071067812 x = -15.071067812 Simplifying x = -15.071067812

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-0.928932188, -15.071067812}

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